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0.965x^2-3x+2=0
a = 0.965; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·0.965·2
Δ = 1.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{1.28}}{2*0.965}=\frac{3-\sqrt{1.28}}{1.93} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{1.28}}{2*0.965}=\frac{3+\sqrt{1.28}}{1.93} $
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